That's a formula. It's the tool you use to calculate the gravitational force between
two masses. It's not looking for a solution, and nobody asked you to solve it.
As soon as you know 'G', m1, m2, and 'r', then you can calculate 'F' .
7.6667
Weight is (acceleration due to gravity) x mass Gravitational force= GM1M2/r2
40
F=GM1M2/R2 dF=GM1dM2/R2 You will find that this is a linear relationship between F and M2. The slope of the line is GM1/R2 the y intercept is 0
Area of a circle equals pi r2 Therefore the radius of a circle equals the square root of (area divided by pi).
0.6369
yes it effects and gravitational pull is inversely proportional to the square of distance between two objects: G = gm1m2 /r2
3ohm
If: r2 = 17 Then: r = the square root of 17
32/10=3.2 or 3 r2
S = 2 pi r h + 2 pi r2S - 2 pi r2 = 2 pi r hh = (S - 2 pi r2) / (2 pi r)
Solving equations in two unknowns (r and h) requires two independent equations. Since you have only one equation there is no solution.