x² - 4x = 41 → x² -4x - 41 = 0
Using the quadratic formula:
x = (-b ± √(b² - 4ac))/(2a)
→ x = (4 ± √(4² - 4×1×-41)/(2×1)
→ x = (4 ± √(4(4+41)))/2
→ x = (4 ± 2√45)/2
→ x = 2 ± √45
→ x = 2 + √45 (≈ 8.708) or x = 2 - √45 (≈ -4.708)
4x = 72.divide both sides by 4x = 18
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
2y = 4x + 4y = 2x + 2
4x = 16Divide each side of the equation by 4:x = 4
It equals 53X- a number is squared when it is multiplied by itself, so 7X by 7X = 49X. 2X by 2X =4X, so 49X + 4X is 53X.
4x = 72.divide both sides by 4x = 18
4x times 4x equals 16x2.
13
x = -½
-31 - 10x = 41 - 4x In algebra what you do to one side of the equation you do the the same as the other First add 31 to both sides -10x = 72 -4x then add 4x to both sides -6x = 72 divide both sides by -6 x = -12
Yes, but the solution is imaginary if you have learned that 4x^2 + 7 = 5 4x^2 = -2 x^2 = -1/2 x = +/-0.707i where i = square root of -1
-12 (?)
-3
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
y=xsquared-4x+2
She isn't. 4x squared is 4 times (x squared). That is, 4 times (3 squared) = 4 times 9. If you want it to be the square of 4x (which would be the square of 4 times 3, ie, 12), you have to write it as (4x)squared.
-31 - 10x = 41 - 4x-31 + 31 - 10x = 41 + 31 - 4x- 10x = 72 - 4x-10x + 4x = 72 - 4x + 4x-6x = 72-6x ÷ -6 = 72 ÷ -6x = -12Check Your Solution:x = -12-31 - 10x = 41 - 4x-31 - 10(-12) = 41 - 4(-12)-31 + 120 = 41 + 48120 - 31 = 41 + 4889 = 41 + 4889 = 89