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To solve the equation x^2 + 4x = 5, we first need to rewrite it in standard form by combining like terms: x^2 + 4x - 5 = 0. Next, we can solve for x by factoring the quadratic equation or using the quadratic formula. Factoring may involve trial and error or the use of the AC method. Alternatively, the quadratic formula, x = (-b ± √(b^2 - 4ac)) / 2a, can be used where a = 1, b = 4, and c = -5 in this case.
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CoachXXXX = X to the fourth power.
Factor out X squared, and you'll get (X squared)(1 + X squared) = 5.
Then set each one equal to five and you'll get two s.
(X squared) = 5, so X = 2.236. (1+X squared) = 5, so X = 2.
AnotherBut if you substitute x=2 into the expression x2+x4=5 you get 4+16=5.If the expression is intended to be x2+4x-5=0 then x=1 and x=25 are solutions Make the substitution y=x2, The equation can then be written as y2+y-5=0. You can then complete the square or apply the quadratic formula. y=[-b+√(b2-4ac)]/2 where a=1, b=1, and c=-5 which upon substitution for a, b, and c becomes
y=[-1+√21]/2=1.791287847=x2; x4=y2=3.208712153 and x2+x4=5
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