i dont no
How do write 666 in standard form?
That is the standard form!
It is In standard form.
It is already in standard form.
It is already in standard form.
6y = 3x + 4
Slope intercept form: y = mx + c where m and c are constants. Subtract y from both sides: 0 = mx + c -y Rearrange: 0 = mx - y + c = standard form.
Square the standard deviations, subtract/add them and calculate the square root of the subtraction/sum. StDV=sqrt (StDvA^2+StDvB^2)
To calculate standard time, subtract the equation of time from the sundial time, then subtract the longitude from the answer you get.
If by "standard form" you mean what people in the US call "scientific notation," it's exactly like whole numbers except the exponents are negative. 0.005463 = 5.463 x 10^-3
416 - 693 = -277
It is already in standard form.
To convert the equation ( y = 58x - 9 ) into standard form ( Ax + By = C ), we can rearrange it. First, subtract ( 58x ) from both sides to get ( -58x + y = -9 ). To have integer coefficients, we can multiply the entire equation by -1, resulting in ( 58x - y = 9 ). Thus, the standard form of the equation is ( 58x - y = 9 ).
9,670 is the standard form.
How do write 666 in standard form?
standard form is y =mx + b 9x - 3y = -12 subtract 9x from both sides -3y = -9x -12 divide both sides by -1 3y = 9x +12 divide both sides by 3 y = 3x +4
First, let's just get it into the form of (a number)*10(a power), not necessarily correct standard form. If we write out 1 million, it's 1,000,000. When we count up the zeros, we see this is 106 Thus we can write 56.34 * 106. But in standard form, the decimal one place from the left. For every place we move the decimal to the left, we must add a 1 from the exponent, and for every place we move it to the right, we subtract a 1. If we move the decimal one to the left, it will be in the correct place, thus we must add 1 from the exponent. When we do this we get 5.634 * 107 Which is 56.34 million in standard form.