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How do you use the elimination method to solve 3r-5s equals -16 and 5r plus 3s equals 64?
Updated: 4/28/2022
3(3r-5s = -16)
5(5r+3s = 64)
Multiply all terms in the first equation by 3 and in the second equation by 5:
9r-15s = -48
25r+15s = 320
Add the equations together in order to eliminate s:
34r = 272
Divide both sides by 34 to find the value of r:
r = 8
Substitute the value of r into the original equations to find the value of s:
Therefore: r = 8 and s = 8
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