To write out the given statement algebraically, you would start by defining the variable for the number, let's say it is represented by 'x'. The equation would be: 6x - 5 < 2x + 10. This equation represents the statement "Six times a number minus five is less than twice the number plus ten" in algebraic form. To solve this inequality, you would isolate the variable 'x' by performing operations to simplify and find the range of values that satisfy the inequality.
the number is 8 2 times 8 = 16 16 minus 5 = 11
3x + (-4) ≥ 2x + 8
It is: 3x = 2x+8 and the value of x is 8
minus 1
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
2n - 4
2x+x=3x
4n-5 (Which is four times a number minus 5)
the number is 8 2 times 8 = 16 16 minus 5 = 11
Twice a number would be written as 2x.
3x + (-4) ≥ 2x + 8
It is: 3x = 2x+8 and the value of x is 8
minus 1
2z
It is "a squared minus eighteen b".
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
Write an algebraic expression for the verbal expression. q squared minus 2 times q