It depends on the voltage. Divide the watt-hours (Wh) by the voltage (V) and you will get the Ampere-hours (Ah). So if the voltage is at 10.8V, divide 47 Wh by 10.8V to get about 4.352 Ah. Finally, convert the Ah to milli-Ah (mAh) by multiplying by 1000 to get 4,352 mAh which is rounded to 4400 mAh.
So 47 Wh at 10.8V is about 4400 mAh.
-UnrivaledShogun.
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4400mah
yes 4.1 wh is larger than 5.33
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it is 2(lw)+2(wh)+2(hl)
You know LW, WH and HL Multiply all three together to give L2W2H2 Then take the principal square root = LWH Now Divide LWH by LW. That gives H. Divide LWH by WH. That gives L. Divide LWH by HL. That gives W.