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Slope is known as rise over run. Rise means the amount of units the y-value (or second dimension) has traveled up the y-axis or down the y-axis. Run means the amount of units the x-value (the first dimension) has traveled forwards or backwards on the x-axis. Take a slope of 2 (can also be written as 2/1) that means it goes up two units as it goes over 1 unit for the whole entire graph. A slope of 5/7 means it goes with a y-value of 5 up and an x-value of 7 over. This can be done for any number even negative numbers. Ok... so now to relate it to a constant rate of change. Imagine the dimensions (x and y values) go on for an infinite amount. The slope will be constant throughout infinity. It will always have the same rise over run... It will always be constant. The rate of change is equivalent to the saying "rise over run". Since the slope is constant over infinity the constant rate of change is the same thing across infinity.
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What is the relationship between unit rates slopes and constant rate of change?
Unit rate, slope, and rate of change are different names for the same thing. Unit rates and slopes (if they are constant) are the same thing as a constant rate of change.
How does finding slope compare to finding the rate of change between two variables in a linear relationship?
The slope of a line is the same thing as the rate of change between two variables in a linear relationship.
What does constant rate mean in math?
It means the same rate. Its going/moving at a constant rate.
How are linear and exponential functions similar?
I'm sorry, I don't have much. I have the same problem. The answer I have so far is they are alike because they both have to have a constant rate as they increase. You can't change the slope or the exponent after going up a graph while graphing.
How do you find the average rate of change for a linear function?
A linear function has a constant rate of change - so the average rate of change is the same as the rate of change.Take any two points, A = (p,q) and B = (r, s) which satisfy the function. Then the rate of change is(q - s)/(p - r).If the linear equation is given:in the form y = mx + c then the rate of change is m; orin the form ax + by + c = 0 [the standard form] then the rate is -a/b.
