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The possibilities are all the counting numbers from the largest 16-digit one to the largest 17-digit one.

99,999,999,999,999,999 minus 9,999,999,999,999,999 = 90,000,000,000,000,000

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Q: How many 17 digit numbers are there using 0-9?

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You just start with seeing how many times the 2 digit number can go into the 1st 2 numbers of the 3 digit number. Then you put how many times the 2 digit number can go into the 1st 2 digits of the 3 digit number up top. It's called long division, which is basically a system of finding how many times you can take away the 2 digit number. Sometimes you can't do the first step above if the hundreds digit is too small. When that happens you just get a zero in that part of the calculation. First deal with the hundreds & tens. Look at 144 divided by 12. The leftmost 2 digits represent 14 tens. You can divide this by 12 to get 1 ten in your answer and a remainder of 2 tens left over from the original 14 tens. Add this spare 2 tens to the 4 in the units column to get 24. This is now thought of as 24 units and you can divide this by 12 to get 2 units. Total answer = 1 ten plus 2 units =12. If you try to divide 108 by 12 then the first step won't go because you can't take 12 from 10. But you simply say the answer is zero with 10 left over. Add on the next bit as above to get 108 and you find you can take 9 twelves from it and get none left. So the answer is 09, or simply 9.

Switch the two numbers round then take away the smaller number from the bigger one: 67-76 76- 67= 09 09-90 90- 09= 81 etc

When dealing with base 2 (a/k/a "binary"), when counting upwards, when a digit goes to 2 it creates a new digit to the left. Examples of base 2 usage: 00 01 10 or 010 011 100 Base 10 means that when counting upwards, when a digit goes to ten it creates a new digit to the left. Examples of base 10 usage: 08 09 10 or 098 099 100 If you were dealing with base 16 (a/k/a "hexidecimal"), when counting upwards, when a digit goes to 16 it creates a new digit to the left. Examples of base 16 usage: 08 09 0A 0B 0C 0D 0E 0F 10 or 0FC 0FD 0FE 0FF 100

It shows each of the 4-digit numbers just once in a 12 hour cycle. If you were asking how many times each digit, 0-9, appears in a 12 hour cycle: 0 - 252 times 1 - 492 times 2 - 312 times 3 - 252 times 4 - 252 times 5 - 252 times 6 - 132 times 7 - 132 times 8 - 132 times 9 - 132 times Assuming that times like 9:52 do not appear as 09:52.

.65>.09 0.65, because if you took the decimal away and all numbers to the right of it, you'd be left with 09 and 65. Well, which one is greater now? ;)

Related questions

Assuming that 00, 01, 02, etc. count as two digit numbers, then there are one hundred (1 through 99 and including 0).If you are not allowed to count 00, 01, 02, 03, 04, 05, 06, 07, 08, or 09 because they simplify to one digit numbers, then you have ten less--so a total of ninety two digit numbers.

No

The Solitude of Prime Numbers was created on 2010-09-09.

If you count 00, 01 though to 09 as 2 digit numbers then you have a 19% chance...There are 100 numbers and 19 contain the number 8....08, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 98ANOTHER ANSWERTwo digit numbers start at 10 and continue to 99. Of these 90 numbers, 18 have at least one 8 in it. That gives 18/90 = 20% chance (exactly).

No.

Yes. The zero is only acting as a place holder.

XII - 12IV - 04IX - 09

I'll get back to you on 8-5-09.

The date 9-9-09 in Roman numerals is IX.IX.IX. If the numbers represent the date 09-09-2009 that would be IX.IX.MMIX

01 02 03 04 05 06 07 08 09

45

You just start with seeing how many times the 2 digit number can go into the 1st 2 numbers of the 3 digit number. Then you put how many times the 2 digit number can go into the 1st 2 digits of the 3 digit number up top. It's called long division, which is basically a system of finding how many times you can take away the 2 digit number. Sometimes you can't do the first step above if the hundreds digit is too small. When that happens you just get a zero in that part of the calculation. First deal with the hundreds & tens. Look at 144 divided by 12. The leftmost 2 digits represent 14 tens. You can divide this by 12 to get 1 ten in your answer and a remainder of 2 tens left over from the original 14 tens. Add this spare 2 tens to the 4 in the units column to get 24. This is now thought of as 24 units and you can divide this by 12 to get 2 units. Total answer = 1 ten plus 2 units =12. If you try to divide 108 by 12 then the first step won't go because you can't take 12 from 10. But you simply say the answer is zero with 10 left over. Add on the next bit as above to get 108 and you find you can take 9 twelves from it and get none left. So the answer is 09, or simply 9.