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Q: How many 2x2 tiles to cover 324 ft?

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1296 Tiles

324

18*18 = 324 tiles.

18inx18in = 324 sqin = 2.25sqft (1 sqft = 144 sqin) 200 / 2.25 = 88.89 tiles

240 sq ft = 240x12x12 = 34560 sq inches Each tikle is 18 x 18 = 324 sq inches Thus you need 34560/324 = 107 tiles

12 sq ft = 1728 sq inches each tile is 18 x 18 = 324 sq in 1728/324 = 5.33 tiles I assume you did mean 12 sq ft not a 12 ft by 12 foot floor which is 144 sq ft or 64 tiles

Assuming you mean 18 inch tiles... 290 square feet is 41,760 square inches. Each tile is 324 square inches - so you would need 129 tiles in total (with a fraction of a tile left over)

each tile is 18 x 18 = 324 sq in room is 63 x 144 = 9072 sq in 9072/324 = 28 tiles

64 tiles for a square shape of 140 square feet each tile equals 18 in x 18 in = 324 sq in 140 sq ft = 140 x (12x12) = 20160 sq in 20160 sq in : 324 sq in = 62.222 tiles sq root of 62.222 = 7.888 tiles per side so you will use 8 tiles per side and will have a leftover of .112

18*18-324 319 square feet = 391*12*12 inches = you solve it yourself.

142.22 tiles First, calculate the number of square inches you need by converting : 320 ft²*144 in² 1 ft²=46,080 in² Second, determine the area of the tiles: 18in * 18in = 324 in² Lastly, divide the total area by the area of the tile to determine the number you need: 46,080 in² / 324 in² = 142.22 tiles

(324)/(depth in inches)

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