81
1296 Tiles
18*18 = 324 tiles.
324
18inx18in = 324 sqin = 2.25sqft (1 sqft = 144 sqin) 200 / 2.25 = 88.89 tiles
240 sq ft = 240x12x12 = 34560 sq inches Each tikle is 18 x 18 = 324 sq inches Thus you need 34560/324 = 107 tiles
12 sq ft = 1728 sq inches each tile is 18 x 18 = 324 sq in 1728/324 = 5.33 tiles I assume you did mean 12 sq ft not a 12 ft by 12 foot floor which is 144 sq ft or 64 tiles
To determine how many 18 by 18 inch tiles are needed to cover an area of 71 feet, first convert the feet into inches: 71 feet is 71 x 12 = 852 inches. The area of one tile is 18 inches x 18 inches = 324 square inches. To find out how many tiles are needed, divide the total area (852 inches) by the area of one tile: 852 / 18 = 47 tiles. Therefore, you would need approximately 47 tiles to cover a measurement of 71 feet.
Assuming you mean 18 inch tiles... 290 square feet is 41,760 square inches. Each tile is 324 square inches - so you would need 129 tiles in total (with a fraction of a tile left over)
64 tiles for a square shape of 140 square feet each tile equals 18 in x 18 in = 324 sq in 140 sq ft = 140 x (12x12) = 20160 sq in 20160 sq in : 324 sq in = 62.222 tiles sq root of 62.222 = 7.888 tiles per side so you will use 8 tiles per side and will have a leftover of .112
each tile is 18 x 18 = 324 sq in room is 63 x 144 = 9072 sq in 9072/324 = 28 tiles
18*18-324 319 square feet = 391*12*12 inches = you solve it yourself.
142.22 tiles First, calculate the number of square inches you need by converting : 320 ft²*144 in² 1 ft²=46,080 in² Second, determine the area of the tiles: 18in * 18in = 324 in² Lastly, divide the total area by the area of the tile to determine the number you need: 46,080 in² / 324 in² = 142.22 tiles