18
twenty-eight (28)
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
8x7x6x5x4x3x2x1
200 different combinations. :)
18
Assuming there can be at most one scoop of each flavour, there are two possible answers: A: The order of the scoops does matter. B: The order of the scoops does not matter. A: 10*9*8 = 720 combination B: 10*9*8/(3*2*1) = 120 combination
If you have n flavors available, you can make n(n-1) different permutations (each flavor can be on bottom or top and its considered different) or n(n-1)/2 different combinations (unique pairs of flavors ignoring order).I think the answer you want is n(n-1)/2.
you can make 27 triple dip cone combinations from three flavours 3 flavors for the first dip x 3 flavors for second x 3 flavors for third dip = 27 combinations
7*3*4 = 84 combinations.
2^35-1=34359738367 (over 34 billion - if you made one a second, it would take about 1090 years to do them all!) This is assuming you only make flavor combinations with equal portions of each used flavor, and that you can use up to all 35 flavors, and not counting "no flavor" as an option. If you allow for varying portions, there is no practical limit to how many different flavors you could make, although many would be indistinguishable to humans.
twenty-eight (28)
64 scoops
Essentially, this is a permutation problem with replacement. The number of permutations can be expressed as n^k, where n is the number of choices and k is the number of spaces. In this case it is 4^3 or 64 permutations.
Two make combinations you would take 2x1=2 combinations only
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.