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81

As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462).

The first digit can be one of any of the 3 numbers.

The second digit can be one of any of the three numbers, as can the third digit and also the fourth.

Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.

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Q: How many 4-digit numbers can be formed by the digits 2 4 6?

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There are 60480 numbers.

1 set

There are 4^6 = 4096 such numbers.

If the digits are all different then 18. Otherwise, 192.

There are 900 of them.

Related questions

99999

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.

There are 5*4*3 = 60 such numbers.

500

24

840

There are 60480 numbers.

180 of them.

There are 3024 of them.

Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.

1 set

There are 4^6 = 4096 such numbers.

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