How many 4 digit odd numbers can you make using digits 5380 without repeating any digit?

Answer 1

16

Answer 2

If the number has to be odd then it must end with either the 3 or the 5. We will assume it can't start with the zero either.

The variations therefore are:

3805

3085

5803

5083

8503

8053

8305

8035

To give a total of 8 numbers.

Answer 3

Oh, dude, let me think about this super tough math problem... So, if we can't repeat digits and we want odd numbers, we need the last digit to be 5 or 3, right? So, that leaves us with 2 choices for the last digit. Then, for the first digit, we have 3 options (5, 3, or 8), and for the middle digits, we have 2 options each. So, that's 2 x 3 x 2 x 1 = 12 odd 4-digit numbers.

Answer 4

To create a 4-digit odd number using the digits 5, 3, 8, and 0 without repetition, the units place must be occupied by the digit 5 (since it is the only odd digit given). The thousands place can be filled by any of the remaining three digits (3, 8, or 0), leaving two options for this place. The remaining two places can then be filled by the two remaining digits, resulting in 2*2 = 4 possible 4-digit odd numbers: 5380, 5308, 5830, and 5803.