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ReneTo calculate the number of 4-number combinations using the numbers 1, 4, 6, and 9 without repetition, you can use the permutation formula. Since there are 4 options for the first number, 3 options for the second number, 2 options for the third number, and 1 option for the fourth number, you would multiply these numbers together: 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different 4-number combinations using the numbers 1, 4, 6, and 9.
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What is the 8th term in the pattern 12 59 294 1469 7344?
It is 917969.
What is 1469 times 4675?
1,469 multiplied by 4,675 is 6,867,575
What number comes next in this pattern 1 5 33 229 1601?
11205 Pattern rule: Start at 1. Multiply by 7, and subtract 2.
What is the 8th term of 12 59 294 1469 7344?
There are an infinite number of possible answers - there are an infinite number of formulae that can be found to give t{1..5} = {12, 59, 294, 1469, 7344} which will give different values for t8. eg: t{n} = (376n⁴ - 3384n³ + 11186n² - 15369n + 7227)/3 gives t{1..5} = {12, 59, 294, 1469, 7344}, and t8 = 135889. t{n} = (-4929n⁵ + 76943n⁴ - 446037n³ +1198513n² -1473498n + 649296)/24 also gives t{1..5} = {12, 59, 294, 1469, 7344}, but t8 = -381656. However, the solution your teacher is probably expecting is based on the fact that: U1 = 12 U{n} = 5U{n-1} - 1 for n ≥ 2 This leads to: t1 = 12 t{n} = 12 + 47 × 5ⁿ⁻² for n ≥ 2 → t8 = 917969
What comes next in this pattern 12 59 294 1469 7344?
You are multiplying by 5 and taking 1 away, so the next value is 36719.
