There are 5760 such numbers.
-123456785
6*5*4*3*2*1=720 possible numbers
3, 7 and 9. 4 odd digits that add up to 19 would be 9, 9, 0.5, 0.5
A number is a multiple of 4 if the last 2 digits are a multiple of 4 The 10s digit is even and the last digit is 0, 4 or 8 The 10s digit is odd and the last digit is 2 or 6 A number is a multiple of 8 if the last 3 digits are a multiple of 8 The 100s digit is even and the last 2 digits are a multiple of 8 The 100s digit is odd and the last 2 digits are 4 times an odd number
There are 5760 such numbers.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
4 x 6 x 5 x 4 = 480 if digits are not to be repeated. 4 x 73 = 1372 otherwise.
192 ways
24
With repeated digits, 43 = 64 Without repeated digits, 4*3*2 = 24
That would be 4! = 4 * 3 * 2 * 1 = 24
3*3*3*3=81
The greatest 4-digit number with no repeated digits is... 9876
Without repeating any of the digits: 4*3*2*1 = 24 If repeated digits are allowed, then 4*4*4*4 = 256
5 is odd in digits and five has 4 alphabets which is even
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.