There are 5760 such numbers.
6*5*4*3*2*1=720 possible numbers
3, 7 and 9. 4 odd digits that add up to 19 would be 9, 9, 0.5, 0.5
A number is a multiple of 4 if the last 2 digits are a multiple of 4 The 10s digit is even and the last digit is 0, 4 or 8 The 10s digit is odd and the last digit is 2 or 6 A number is a multiple of 8 if the last 3 digits are a multiple of 8 The 100s digit is even and the last 2 digits are a multiple of 8 The 100s digit is odd and the last 2 digits are 4 times an odd number
If the number can contain repeated digits, the answer is 800000. Without repetition, there are 483840.
There are 5760 such numbers.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
4 x 6 x 5 x 4 = 480 if digits are not to be repeated. 4 x 73 = 1372 otherwise.
192 ways
24
With repeated digits, 43 = 64 Without repeated digits, 4*3*2 = 24
That would be 4! = 4 * 3 * 2 * 1 = 24
3*3*3*3=81
The greatest 4-digit number with no repeated digits is... 9876
Without repeating any of the digits: 4*3*2*1 = 24 If repeated digits are allowed, then 4*4*4*4 = 256
5 is odd in digits and five has 4 alphabets which is even
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.