There are 45 such numbers.
There are 45 combinations.
45 of them.
To calculate the number of combinations of 4 numbers out of 45, we use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 45 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, we get 45C4 = 45! / (4!(45-4)!) = 45! / (4!41!) = (45 x 44 x 43 x 42) / (4 x 3 x 2 x 1) = 1,086,132. Therefore, there are 1,086,132 possible combinations of 4 numbers chosen from 45.
To find four numbers that add up to 45, we can set up an equation: x + y + z + w = 45. Since we are looking for four numbers, we need to consider different combinations. One possible solution is 10 + 11 + 12 + 12 = 45. Another solution could be 8 + 9 + 10 + 18 = 45. There are multiple combinations that satisfy this condition.
45.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
There are 45 such numbers.
About 13million,
There are 45 combinations.
5 digit combinations for numbers 1 to 50= 50 C 5N!= 1x2x3x4x...x (N-1) x N= (50!)/(45!x5!) =(50x49x...x2x1)/((45x44x...x2x1)(5x4x3x2x1))=(50x49x48x47x46)/(5x4x3x2)=254251200/120 =21187602118760 combinations
There are 45 such numbers.
Any 6 from 45 = 814506045C6 = 8145060
45
45 of them.
There are 45 of them.
45