Well if there is 12x 5s in a minute and 60 minutes in an hour (12x60=720) and there are 24 hours in a day then its 720x24=
17, 280
101
There are: 120/5 = 24
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
21 5s
To determine how many 5s are in 3, we need to perform division. However, since 3 is less than 5, there are no complete 5s in 3. In other words, the quotient of 3 ÷ 5 is 0 with a remainder of 3. Therefore, there are zero 5s in 3.
101
24
48 minutes in 4/5 of a hour.
There are: 120/5 = 24
To work out 5s in a 24-hour format on a digital clock, you can look for the times that contain the digit '5' in either the hour or minute sections. The hours range from 00 to 23, and the minutes range from 00 to 59. Therefore, the possible hours that include '5' are 05, 15, and the minutes include any time from 05, 15, 25, 35, 45, and 55. By combining these, you can identify specific times like 05:00, 05:05, 15:55, etc.
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
21 5s
well here is how i wud do it................ 5 x 5 - 1 = 24
To determine how many 5s are in 3, we need to perform division. However, since 3 is less than 5, there are no complete 5s in 3. In other words, the quotient of 3 ÷ 5 is 0 with a remainder of 3. Therefore, there are zero 5s in 3.
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.
20
90