5
Five 7s can go into 35. This is because when you divide 35 by 7, the result is 5 (35 ÷ 7 = 5). Therefore, you can fit five 7s into 35 without exceeding it.
5
No. There are ~37.57 of them.
There are 3168 such numbers. 2673 have one 7 459 have two 7s 35 have three and 1 has all four 7s. Numbers with leading 0s are excluded.
5.28751 7s equals 37.
5x7=35, then 3-1=2, so 35+2=37
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
6
80.
18
14
answer:4