To determine how many times 8 can go into 49, we need to perform division. 49 divided by 8 equals 6 with a remainder of 1. This means that 8 can go into 49 exactly 6 times with 1 left over.
8 with remainder 1.
Exactly 49 times
49 divided by 8 equals 6 with a remainder of 1.
49 ÷ 8 = 6 remainder 1
8 with remainder 1.
49 divided by 8 equals 6 with a remainder of 1.
49 ÷ 8 = 6 remainder 1
49 divided by 6 equals 8 with a remainder of 1.
8 with remainder 24.
Exactly, 5x 8 + 3x 3
8 and 1/6
392
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.
8 with 1 remaining 49 - 1 = 48 = 6 x 8
200 divided by 25 = 8
7 goes into 28 4 times