If you're in Celsius, 13459.5 Btu's. If you're in Fahrenheit, 12632.5 Btu's.
25
100 BTU if it's Fahrenheit
212-65=147. 147(20)=2940 btu needed is this right?
.12
300
25
2250
6,520 Btus
That will completely depend on how much water there is.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
It depends on the volume of the room.
The question cannot be answered because:the temperature scale being used has not been specified,There is no normal temperature scale in which you can have ice at 32 degrees and steam at 82 degrees without large changes in pressure. If changes in pressure are permitted then there is no simple formula to calculate the amount of heat (btus) required.
10 x (70 - 50) = 200 Btu
313 Btu
1 btu raises 1 lb water 1 degree F from 62 to 63 degrees. generally 1 btu/lb/degree F x 20 degrees F difference x 15 lbs = 300 btus specifically the heat of the liquid at 100F is 67.97 btus and at 120F = 87.92 btu 87.92 - 67.97 = 19.95 btu 19.95 x 15 lbs. = 299.25 btus to be more accurate
100 BTU if it's Fahrenheit