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How many air molecules are in a 13 x 12 x 10ft room Assume atmospheric pressure of 1 00 ATM a room temperature?
Wiki User
∙ 9y ago
To solve this problem, several different steps must be taken.
Convert Volume = 13*12*10 = 1560ft^3 * 28.2 = 43992L ~28.2 Litres per cubic ft
Ideal Gas Equation: PV=nRT Rearrange: n=PV/RT Temperature:273+20=293K
n=[(1*43992)/(0.0821*293) = 1828.78
1 mol Air Molecules = 6.022*10^23 Air Molecules
1828.78*(6.022*10^23) = 1.10 * 10^27
Wiki User
∙ 9y ago
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