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Five (5) have one or the other but not both.

Six (6) have both.

Total of eleven (11).

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โˆ™ 2010-09-04 18:26:42
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many bit strings of length 8 contain either three consecutive 0s or four consecutive 1s?
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How many bit strings are there of length eight?

Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.


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How many bit strings of length 8 contain exactly three 1's?

56 The number of triples of 1s on 8 bits


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How many bit strings are there of length ten?

210=1024


How many different bit strings are there of length 7?

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How many strings of length 0 that start with 1 bit or end with 2 bits are possible?

There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.


How many strings are there of lower case letters of length 4 or less?

By the sum rule we can count the number of strings of length 4 or less by counting the number of strings of length i, for 0 <= i <= 4, and then adding the results. Now there are 26 letters to choose from, and a string of length i is specified by choosing its characters, one after another. Therefore, by the product rule there are 26^i strings of length i. The answer to the question is thus: sum i=0 to 4 ( 26^i = 1 + 26 + 676 + 17576 + 456976) = 475,255.

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