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Five (5) have one or the other but not both.

Six (6) have both.

Total of eleven (11).

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Q: How many bit strings of length 8 contain either three consecutive 0s or four consecutive 1s?
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How many bit strings are there of length eight?

Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.


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