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Q: How many bit strings of length 8 contain either three consecutive 0s or four consecutive 1s?

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Length and width.

there are 128 (2 to the power of 7) bit strings of length 7

-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.

2 x 2 x 13

Length = 4, Width = 2

Related questions

Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.

No, because of the strings weight and length, they are caused to be either high or low. -Red Mist

Character string values storage:1. CHAR:§ Stores strings of fixed length.§ The length parameter s specifies the length of the strings.§ If the string has smaller length it padded with space at the end§ It will waste of a lot of disk space.§ If the string has bigger length it truncated to the scale number of the string.2. VARCHAR:§ Stores strings of variable length.§ The length parameter specifies the maximum length of the strings§ It stores up to 2000 bytes of characters§ It will occupy space for NULL values§ The total length for strings is defined when database was created.3. VARCHAR(2):§ Stores strings of variable length.§ The length parameter specifies the maximum length of the strings§ It stores up to 4000 bytes of characters§ It will not occupy space for NULL values§ The total length of strings is defined when strings are given

56 The number of triples of 1s on 8 bits

Length and width.

2X26

52

1024

210=1024

there are 128 (2 to the power of 7) bit strings of length 7

There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.

By the sum rule we can count the number of strings of length 4 or less by counting the number of strings of length i, for 0 <= i <= 4, and then adding the results. Now there are 26 letters to choose from, and a string of length i is specified by choosing its characters, one after another. Therefore, by the product rule there are 26^i strings of length i. The answer to the question is thus: sum i=0 to 4 ( 26^i = 1 + 26 + 676 + 17576 + 456976) = 475,255.

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