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21 bits.
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What is the minimum number if binary bits required to represent the decimal number 250?
8
What is the maximum number that you can count up to using 10 bits14 bits and count up to a maximum of 511 63?
Using n bits, you can count to 2n - 1. This is for unsigned integers. So 10 bits = 210 - 1 = 1023 14 bits = 214 - 1 = 16383 To count to 511 you need log2(511+1) = log2(512) = 9 bits. To count to 63 you need log2(63+1) = log2(64) = 6 bits.
Decimal equivalent of the largest binary integer that can be obtained with 11 bits?
What is the decimal equivalent of the largest binary integer that can be obtained with (a) 11 bits and (b) 25 bits?
What is the smallest decimal number that can be stored using 8 bits?
0.0000001
What is the Largest decimal number that can be represented using 16 bits in BCD?
65,535
How many binary bits are required to represent the decimal number 643?
Count them: 643(10)=1010000011(2)
What is the minimum number of bits required to represent the decimal 1000?
9 bits
How many bits are required to represent 32 digit decimal number?
103
How many binary digits are required to count to decimal 15?
Assuming you start from 0, you need at least 4 bits. 15 in binary: 15 = 8 + 4 + 2 + 1 = 1111₂
What is the minimum number if binary bits required to represent the decimal number 250?
8
What is the minimum number of bits required to represent the following decimal number 101000?
17 bits would allow a value up to 131071.
How many bits are needed to represent decimal value ranging from 0 to 12500?
how many bits are needed to represent decimal values ranging from 0 to 12,500?
How many bits are required in decimal numbers in range 0 to 999 using Straight binary code and BCD code?
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
The minimum number of bits required to store the hexadecimal number FF is?
Count them: FF(16)=255(10)=11111111(2)
How many decimal numbers can be represented by 4-bits?
There are 16 decimal numbers that can be represented by 4-bits.
What is the maximum number that you can count up to using 10 bits14 bits and count up to a maximum of 511 63?
Using n bits, you can count to 2n - 1. This is for unsigned integers. So 10 bits = 210 - 1 = 1023 14 bits = 214 - 1 = 16383 To count to 511 you need log2(511+1) = log2(512) = 9 bits. To count to 63 you need log2(63+1) = log2(64) = 6 bits.
How many bits are needed to represent decimal 200?
8 bits if unsigned, 9 bits if signed
