21 bits.
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8
Using n bits, you can count to 2n - 1. This is for unsigned integers. So 10 bits = 210 - 1 = 1023 14 bits = 214 - 1 = 16383 To count to 511 you need log2(511+1) = log2(512) = 9 bits. To count to 63 you need log2(63+1) = log2(64) = 6 bits.
What is the decimal equivalent of the largest binary integer that can be obtained with (a) 11 bits and (b) 25 bits?
0.0000001
65,535