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How many calories are needed to raise the temperature of 10 g of water from 25 C to 35 C?
100 calories.
1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
What else can I help you with?
How many btu are needed to raise 15lb of water from 100 to 120 degrees F?
300
How many calories to 1 gallon of water?
Pure water contains no calories.
How many calories to raise 1 quart of water 38 degrees?
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
How many btu is neede to raise 20 pounds of water from 65 to 212 degrees?
212-65=147. 147(20)=2940 btu needed is this right?
How many btus to raise 1 pound of water from room temp deg to steam 213 deg?
First convert 1 lb of water to lb-moles which is 0.055 lb-moles (you'll need this later). This problem can be broken into 3 steps:(1) You need to detemine how much heat is needed to raise room temperature water (68oF) to 212oF. This can be used using the heat capacity of water which at room temperature is 1 Btu/lboF. So the amount of heat needed for this is:Q1 = m*Cp*ΔT= (1 lb)*(1 Btu/lboF)*(212 - 68oF)= 144 Btu(2) Next you need to account for the phase change. The water changes to steam at 212oF. You use the heat of vaporization which you can look up in any Chemistry or Chemical Engineering Handbook. The Hvap that I found is 17493.5 Btu/lb-mole.Q2 = n(lb-moles)*Hvap= (0.055 lb-moles)*(17493.5 Btu/lb-mole)= 972.64 Btu(3) Next you need to find out how much heat is needed to raise the temperature of the steam from 212 to 213oF. You can look up the heat capacity of steam at 212oF to be 0.485 Btu/lboF.Q3 = m*Cp*ΔT= (1 lb)*(0.485 Btu/lboF)*(213-212oF)= 0.485 BtuTo find the total heat needed add Q1+Q2+Q3 (144+972.64+0.485) =1117.12 Btu
How many calories of heat needed to raise temperature of 8.1 g of water 20C?
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
How many calories does it take to raise the temperature of a cup of water?
It depends on what temperature is is at and how much water there is.
How many calories are required to raise the temperature of 1 g of water by 5drgress c?
1 Calorie is equal to 1000 calories one is a big C the other is a small c and 1 Calorie is needed to raise 1gram of water; 1 Degree C* so your answer is 5 Calories or 5000calories
If water contains no calories then Einsteins equation must be wrong?
There are two different kinds of calories, cal or Cal. Einstein uses calories (cal) as the energy needed to raise the temperature of 1 gram of water through 1 degree Celsius. The large calorie (Cal) is the energy needed to raise the temperature of 1 kilogram of water through 1 degree Celsius. This large calorie (Cal) is equal to one thousand small calories and often used to measure the energy value of foods.
How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.
What is the total number of calories of heat needed to raise to raise the temperature of the liquid water from 20 degrees Celsius to 30 degrees Celsius?
To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
What is the number of calories needed to raise one gram of water by one degree Celsius?
1
How many calories does it take to raise the temperature one gram of water from freezing point to the boiling point?
The value is 100 calories.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
Is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.?
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
How were calories were made?
calories were never "made." they are simply the amount of energy required to raise the temperature one gram of water one degree celsius.
