100 calories.
1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
300
Pure water contains no calories.
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
To calculate the heat required to raise the temperature of 10 pounds of water from 50°F to a specific temperature, you can use the formula: [ Q = mc\Delta T ] where ( Q ) is the heat energy (in BTUs), ( m ) is the mass (in pounds), ( c ) is the specific heat capacity of water (approximately 1 BTU/lb°F), and ( \Delta T ) is the change in temperature (in °F). For example, if you want to raise it to 150°F, the temperature change (( \Delta T )) would be 100°F, so the heat required would be: [ Q = 10 , \text{lb} \times 1 , \text{BTU/lb°F} \times 100°F = 1000 , \text{BTUs} ] Adjust ( \Delta T ) based on your target temperature.
212-65=147. 147(20)=2940 btu needed is this right?
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
It depends on what temperature is is at and how much water there is.
1 Calorie is equal to 1000 calories one is a big C the other is a small c and 1 Calorie is needed to raise 1gram of water; 1 Degree C* so your answer is 5 Calories or 5000calories
There are two different kinds of calories, cal or Cal. Einstein uses calories (cal) as the energy needed to raise the temperature of 1 gram of water through 1 degree Celsius. The large calorie (Cal) is the energy needed to raise the temperature of 1 kilogram of water through 1 degree Celsius. This large calorie (Cal) is equal to one thousand small calories and often used to measure the energy value of foods.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
1
The value is 100 calories.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.