That depends on the box.
25
Only one.
3x3x8=72 cubes 63 Cubes
0 - you said it's only 1 cube even if it's a big one
488 cubes
You can make four.
25
4
Give us the dimensions of the prism.
Only 1.
Only one.
The line of 1000000 centimeter cubes would be 1000000 centimeters long.
3x3x8=72 cubes 63 Cubes
2 layers would fit in the prism and each layer would have 15 cubes. Total: 30 cubes.
8 cubes in total (two layers). (If a third layer is added, the cubes would be 1 inch above the box.)
I am assuming that your question states that the top and sides are painted red but the bottom isn't. If so, the answer is:- There are no cubes with 4 faces painted, the most that can be painted is 3 for the ones on the corners. There are 4 corners at the top of the cube that will have their top and 2 sides painted. Therefore there are 4 cubes with 3 painted. The cubes at the corners on the second and third row down will have 2 faces painted, as will the middle cubes on the top row so there are 12 of them in this puzzle. The cube in the middle of each painted face will have just one face painted so this is 5 (assuming the bottom isn't painted). The cubes in the middle of the bottom row will also have one face painted. This brings the total to 9 That is the total of cubes that have paint on them... 4+12+9 = 25 There are 27 cubes in your puzzle so only 2 have no painted faces. The cube right in the middle and the cube in the middle of the bottom layer.
There are 7 layers in the OSI model which are from top to bottom: application layer / presentation layer / session layer / transportation layer / network layer / data link layer / physical layer