To calculate the number of combinations of 5 numbers possible from 1 to 20, we use the formula for combinations, which is nCr = n! / (r!(n-r)!). In this case, n = 20 and r = 5. Plugging these values into the formula, we get 20! / (5!(20-5)!) = 20! / (5!15!) = (20x19x18x17x16) / (5x4x3x2x1) = 15,504 possible combinations.
Oh, what a lovely question! Let's see here... To find the number of combinations of 5 numbers from 1 to 20, you can use the combination formula which is 20 choose 5. This equals 15,504 possible combinations. Isn't that just delightful? Just imagine all the beautiful possibilities waiting to be explored!
There are 167960 combinations.
There are 1140 five digit combinations between numbers 1 and 20.
There are 45 combinations.
4+4+4+4+4= 20
There are 6C3 = 20 such combinations.
There are 167960 combinations.
There are 125970 combinations and I am not stupid enough to try and list them!
There are 167960 9 digits combinations between numbers 1 and 20.
86,450
Twenty factorial which is denoted by "20!". 20! = 1x2x3x4x5x6x7x8x...x19x20
There are 1140 five digit combinations between numbers 1 and 20.
20 and 30, among other possible combinations.
There are 45 combinations.
20 and 30, among other possible combinations.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
To calculate the number of 3-number combinations from the numbers 1-20, we can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 and r = 3. Plugging these values into the formula, we get 20C3 = 20! / 3!(20-3)! = 1140. Therefore, there are 1140 possible 3-number combinations from the numbers 1-20.
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.