To find the number of combinations of dimes, nickels, and pennies that equal 19 cents, we can use a systematic approach. Let's denote the number of dimes as D, nickels as N, and pennies as P. Since 1 dime is equivalent to 10 cents, 1 nickel to 5 cents, and 1 penny to 1 cent, we can set up the equation 10D + 5N + 1P = 19. To solve this equation, we can use techniques such as trial and error, substitution, or elimination to determine the possible combinations.
9 combinations. 23 pennies 1 nickel 18 pennies 2 nickels 13 pennies 3 nickels 8 pennies 4 nickels 3 pennies 1 dime 13 pennies 2 dimes 3 pennies 1 dime 2 nickels 3 pennies 1 dime 1 nickel 8 pennies
1 Dime, 1 Nickel, 2 Pennies 1 Dime, 7 Pennies 3 Nickels, 2 Pennies 2 Nickels, 7 Pennies 1 Nickel, 12 Pennies 17 Pennies The answer is 6 different combinations!
9 ways 2 dimes and 3 cents 1 dime and 2 nickels and 3 cents 1 dime and 1 nickel and 8 cents 1 dime and 13 cents 4 nickels and 3 cents 3 nickels and 8 cents 2 nickels and 13 cents 1 nickel and 18 cents 23 cents
It equals 93 cents!
16 nickels equal 80 cents plus 42 cents equals 122 cents so the final answer is 7 dollars and 22 cents
9 combinations. 23 pennies 1 nickel 18 pennies 2 nickels 13 pennies 3 nickels 8 pennies 4 nickels 3 pennies 1 dime 13 pennies 2 dimes 3 pennies 1 dime 2 nickels 3 pennies 1 dime 1 nickel 8 pennies
There are 12 different combinations using pennies, nickels and dimes. 25 pennies 20 pennies and 1 nickel 15 pennies and 2 nickels 15 pennies and 1 dime 10 pennies and 3 nickels 10 pennies 1 dime and 1 nickel 5 pennies and 4 nickels 5 pennies 1 dime and 2 nickels 5 pennies and 2 dimes 5 nickels 1 dime and 3 nickels 2 dimes and 1 nickel
1 Dime, 1 Nickel, 2 Pennies 1 Dime, 7 Pennies 3 Nickels, 2 Pennies 2 Nickels, 7 Pennies 1 Nickel, 12 Pennies 17 Pennies The answer is 6 different combinations!
Seven combinations that I can come up with: two dimes a nickel and three pennies all pennies two dimes and eight pennies a quarter and three pennies five nickels and three pennies three nickels one dime and three pennies two nickels one dime and eight pennies
9 ways 2 dimes and 3 cents 1 dime and 2 nickels and 3 cents 1 dime and 1 nickel and 8 cents 1 dime and 13 cents 4 nickels and 3 cents 3 nickels and 8 cents 2 nickels and 13 cents 1 nickel and 18 cents 23 cents
It equals 93 cents!
16 nickels equal 80 cents plus 42 cents equals 122 cents so the final answer is 7 dollars and 22 cents
The answer is four nickels, two quarters, and five pennies equals seventy cents. I had help!
There are 43 combinations of various quantities of quarters (0, 1 or 2), dimes (0 to 5), nickels (0 to 10) and pennies (2 to 52) that make 52 cents.
There are 13 different combinations. For any combination, the number of pennies P, nickels N, Dimes D, and Quarters, P + 5N +10D + 25Q = 25 (1, 5, 6, 1) where P = 0, 5, 10, 15, 20, 25 N = 0 to 5 D = 0 to 2 Q = 0 or 1 The combinations are 1 quarter 2 dimes and 1 nickel 2 dimes and 5 pennies 1 dime and 3 nickels 1 dime, 2 nickels, 5 pennies 1 dime, 1 nickel, 10 pennies 1 dime, 15 pennies 5 nickels 4 nickels, 5 pennies 3 nickels, 10 pennies 2 nickels, 15 pennies 1 nickel, 20 pennies 25 pennies
Twenty pennies Fifteen pennies, one nickel Ten pennies, two nickels Ten pennies, one dime Four nickles Three nickels, five pennies Two nickles, one dime Two dimes One dime, one nickel, five pennies
Assuming only the use of currently produced US coins, there are 9 combinations: 21 pennies 16 pennies, 1 nickel 11 pennies, 2 nickels 11 pennies, 1 dime 6 pennies, 3 nickels 6 pennies, 1 nickel, 1 dime 1 penny, 4 nickels 1 penny, 2 nickels, 1 dime 1 penny, 2 dimes If you allowed the use of obsolete denominations (half cents, 2 cent pieces and 3 cent pieces) the number would be higher, and if you further differentiated between different coins of the same denomination (e.g., large cents vs small cents, three cent silver vs 3 cent nickels, half dimes vs nickels, etc.) the number would be higher still.