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In a bit string length 12 How many begin with 110?
You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.
How many bit strings of length 8 are there which begin with a 0 and end with a 0?
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
How many bit strings of length not exceeding n consist entirely of 1s?
n+1 (counting the empty string)
How many bit strings of length 10 both begin and end with one?
Since there are 8 bits in between, and they can assume any of the two values (0 or 1), that results in a total of 28 different combinations.
How many bit strings are there of length six or less not counting the empty string?
That's just the highest number that can be counted with 6 bits ... 127 .
How many bit strings are there of length eight?
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
How many bit strings of length 10 have?
1024
In a bit string length 12 How many begin with 110?
You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.
How many bit strings are there of length ten?
210=1024
How many bit strings of length 8 ends with a 0?
Half of them.
How many strings of length 0 that start with 1 bit or end with 2 bits are possible?
There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.
How many bit strings of length 11 have more 0s than 1s?
1024 of them.
How many bit strings of length 10 have more 0s than 1s?
There are 210.
How many bit strings of length 8 are there which begin with a 0 and end with a 0?
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
How many bit strings of length not exceeding n consist entirely of 1s?
n+1 (counting the empty string)
How many bit strings of length ten both begin and end with 1?
its 2 raised to power 8 i.e 256
How many bit strings of length 8 contain exactly three 1's?
56 The number of triples of 1s on 8 bits
