its 2 raised to power 8 i.e 256
How many strings of three digits are there? 000 to 999, or a total of 1000. How many strings of three digits contain the same three digits? That's 000, 111, 222 ... 999! ten in total. The difference is your answer: 1000-10 = 990.
There are 256 bytes (8-bit strings), corresponding to the decimal numberszero through 255.Only the byte representing zero is composed of all zeros. All of the remaining255 bytes have at least one ' 1 '.
100
The answer depends on how many numbers are on the spinner.
There are 4*4*3*2*1 = 96 such numbers.
To find the number of bit strings of length 10 that begin and end with "1", we fix the first and last bits as "1". This leaves us with 8 bits in the middle, which can each be either "0" or "1". Therefore, there are (2^8 = 256) different combinations for the 8 middle bits. Thus, there are 256 bit strings of length 10 that begin and end with "1".
You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.
Since there are 8 bits in between, and they can assume any of the two values (0 or 1), that results in a total of 28 different combinations.
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
1024
There are (2^5) bit strings of length 5, as each bit can be either 0 or 1. Therefore, the total number of bit strings is (32).
210=1024
Half of them.
A parachute needs four strings. However, redundancy is best, both for safety and control of the chute. Thus, 16 striings is better, 32 even moreso. Washers around groups of strings cuts down on the likelihood of entanglement. The length of the strings matters, as well (and so does the diameter of the parachute).
There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.
Five (5) have one or the other but not both. Six (6) have both. Total of eleven (11).