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Infinitely many ways!

Suppose you have the fraction 2/d.

Pick any pair of integers a and b where b � 0.

Then 2b-ad is and integer, as is bd so that (2b - ad)/bd is a fraction.

Consider the fractions a/b and (2b - ad)/bd

Their sum is

a/b + (2b-ad)/bd = ad/bd + (2b-ad)/bd = 2b/bd = 2/d - as required.

Since a and b were chosen arbitrarily, there are infinitely many possible answers to the question.

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10y ago
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Anonymous

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4y ago

I think that there are only three ways

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Anonymous

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4y ago

2

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50

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Anonymous

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2/9

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Sjsbsb

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Q: How many different ways can you write a fractions that has a numerator of 2 as a sum of fractions?
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