-99
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There are 3 digits in the numbers 100-199. The hundreds place is always occupied, the tens place can be 0-9, and the ones place can also be 0-9. Therefore, there are 10 options for the tens place and 10 options for the ones place, resulting in 10x10=100 numbers between 100 and 199.
There are infinitely many possible answers. One possible answer is 100, 100, 100, 100, 100, 100, 100, 100, 199.
There are 100 odd numbers between 1 and 199. This can be calculated by dividing the total range (199 - 1 = 198) by 2, as odd numbers are spaced every two integers. Therefore, 198 divided by 2 equals 99, representing half of the odd numbers in the range. Multiplying this by 2 gives us the total count of odd numbers, which is 100.
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
190
1 - 9 = 1 10-19 = 10 20-99 = 8 So...0 - 99 = 19 100 - 199 = 100 + 19 = 119 200 - 299 = 19 300 - 399 = 19 400 - 499 = 19 500 = 0 So, in 1 - 500, the number 1 shows up this many times: 100 + (19 * 5) = 100 + 95 = 195 times