The way to be sure you have one of these is to take any three distinct prime numbers and multiply them. Those three prime numbers are then the only factors the product can have. An example is the number 30, which has factors of 2, 3 and 5.
Factors are prime numbers. The primes hidden in the number 30 are: 2,3, and 5.
To find the HCF of 20 and 30, break them down into their prime factors: 20 = 2x2x5 30 = 2x3x5 The next step is to identify any common prime factors. In this case both numbers have a 2 and a 5 as prime factors. Multiply these together and you get: 2x5 = 10 Therefore the HCF of 20 and 30 is 10.
no, they both have 5 as factors
20 = 2 x 2 x 5 30 = 2 x 3 x 5 Common prime factors: 2 and 5.
Three.
30 is the first with three distinct prime factors.
The prime factorization of 150 is 2 * 3 * 5^2. The distinct prime factors are 2, 3, and 5. To find the product of these distinct prime factors, you simply multiply them together: 2 * 3 * 5 = 30. Therefore, the product of the distinct prime factors of 150 is 30.
There are an infinite number of them. 8 has three prime factors, 30 is the first with three distinct prime factors.
There are an infinite number of them. 8 has three prime factors, 30 is the first with three distinct prime factors.
30 has three prime factors. The prime factors are 2,3,5.
30
30
How about: 2*3*5 = 30
The only number between 30 and 40 with distinct prime factors which add up to 12 is 35.
2*3*5 = 30
2 x 3 x 5 = 30