Since it has 9 faces it is a nonahedron. Not sure how many of the thousands of nonahedrons have 6 vertices.
Nonahedron
A nonahedron. There are many possible configurations: the simplest two to visualise are an octagonal based pyramid and a heptagonal prism.
nonahedron
it has six faces
A nonahedron.
A polyhedron with 9 faces: a nonahedron.A polyhedron with 9 faces: a nonahedron.A polyhedron with 9 faces: a nonahedron.A polyhedron with 9 faces: a nonahedron.
a nonahedron.
Since it has 9 faces it is a nonahedron. Not sure how many of the thousands of nonahedrons have 6 vertices.
Nonahedron.
Nonahedron
A nonahedron. There are many possible configurations: the simplest two to visualise are an octagonal based pyramid and a heptagonal prism.
A nonahedron, which is a 3D shape with 9 faces.
It is a very irregular enneahedron or nonahedron - a shape with 9 faces.
nonahedron
A nonahedron is a nine faced polyhedron. A nonahedron is also known as a enneahedron. There are 2606 distinct convex nonahedra.
Let's suppose you mean How many vertices does a nonahedron have? And the answer is, It depends. A nonahedron is a solid with nine faces. There is no regular nonahedron (look up "Regular solid" anywhere, say on Wikipedia). You could make a nonahedron bytaking a cube (6 square faces, 12 vertices) and slicing off 3 of the vertices to add 3 triangular faces (and making their adjacent original faces no longer square); this solid has 16 verticestaking a regular octahedron (8 triangular faces, 6 vertices) and slicing off one vertex to add one square face (the four adjacent original faces are now trapezoids): 9 verticesshaving down 5 of the edges to add 5 long narrow faces... and I can't visualize this one well enough to count the verticesor slicing off all 4 vertices (adding 4 small triangular faces and making the original faces hexagonal) and shaving one edge (adding a long rectangular face and changing the faces at the ends of the original edge from small triangles to trapezoids): 14 vertices, if I've got it right.taking a tetrahedron (4 faces, 6 edges, 4 vertices) andor countless other ways, yielding many different counts of vertices. ... Well, I'm sure they could be counted, but I'm not about to do it now.