To express 68 as a product of 2 factors, we need to find all pairs of numbers that multiply to 68. The pairs are: 1 and 68, 2 and 34, 4 and 17, and 17 and 4. These pairs give us the following expressions: 1 x 68, 2 x 34, 4 x 17, and 17 x 4.
I prefer to show my divisors as factor pairs, to make it less likely to forget any. 1 and 68 2 and 34 4 and 17 That is all of it.
The factor pairs of 765 are: 1 × 765 3 × 255 5 × 153 9 × 85 15 × 51 17 × 45
The number that goes into 153, 170, and 187 is 17. This is because 153 ÷ 17 = 9, 170 ÷ 17 = 10, and 187 ÷ 17 = 11, resulting in whole number quotients for each division. Therefore, 17 is the common factor that divides evenly into all three numbers.
Only two factors which are itself and one because 17 is a prime number
17 is a prime number, so the only factor pair is 1 x 17.
1 and 17
1 x 17, 17 x 1 (17 is a prime number).
17 has one factor pair, 1 and 17.
(68, 1) (34, 2) (17, 4)
1 and 17.
There are 2 factor pairs of 34:34 = 1 x 3434 = 2 x 17
The factor pair of 17 is 1*17. Because 17 is prime, it has only one factor pair.
To find the factorization of a number, list the factor pairs. 1 x 85 5 x 17 The factors are 1, 5, 17, 85.
85 = 1*85, 5*17
(1, 51) (3, 17)
1 and 85 5 and 17