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Assuming that you can use each number multiple times, 3125, because there

are five options for the first number, five for the second, and so on to reach

five. Then, five times five times five times five times five, or five to the fifth

power, equals 3125.

Were you only able to use each number once, the answer would be 120 based

on the same principle. There would be five options for the first number, four

remaining options for the second, three for the third, two for the fourth, and

then one for the fifth. Then, as with the first, five times four times three times

two (times one, but that really isn't necessary) results in 120.

Q: How many five digit numbers can you make by arranging the numbers 4 1 6 9 and 3?

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ccsndf

720 of them.

11 and 16.

The first digit can be any one of 1,2,3,4,5. With each choice of digit1, the second digit can be any one of 1,2,3,4,5 so making 5*5 two-digit numbers. With each of these, the third digit can be any one of 1,2,3,4,5 so making 5*5*5 three-digit numbers and so on. The total number is 55 = 3125.

40 and 43, among others.

Related questions

Answer is 120 (5x4x3x2x1)

Not sure what a "didget" is. It is possible to make 18 5-digit numbers.

162

55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.

25

ccsndf

120

by multiplying how many digits there are to the fourth power and dividing that by 4 get 64. so u can possibly make 64 combinations... it think

A digit is that which we used to count numbers.

With 123 digits you can make 123 one-digit numbers.

what is the greatest 4-digit number you can make with the digit 0,1,2,3, and 4

Zero - all five digit numbers are higher than 4000.