he trains for 6 hour a day in a week he trains 42 hours
1200 divided by h times s
Obviously the answer depends on the number of stops and the speed of the train. Assuming there are no stops and the the trains run at 70 mph, the answer is about an hour and a half.
1140 minutes [I solve the problem in hours and convert to minutes at the end, just to make the numbers smaller.] 3 seconds per minute=3 minutes per hour So the lateness of the train (in minutes) is given by: Minutes late=3+3t, where t is the time in hours. We want to find the point where the train is 60 minutes (which equals one hour) late: 60=3+3t 60-3=3t 57=3t t=57/3=19 So in 19 hours (=19*60=1140 minutes), the train will be 60 minutes, or one hour, late.
The train is running 4 minutes late. It "needs" to be running 1/2 hours, or 30 minutes late. So it needs to lose 26 minutes, or 26*60 = 1560 seconds. It loses 4 seconds per minute. So it loses 1560 seconds in 1560/4 = 390 minutes = 61/2 hours.
6hours
30 -35
Anywhere from 6 to 14 hours per day, depending on stamina.
1 hour of workout in the gym or cardio in the morning and about 3 hors of practice
they train for about 2 hours everyday apart from sundays.
6 hours
Around 4.5 hours by bus and around 2:15 hours by train.
About 3 hours.
Around 2 hours
6.5 hours
Seven and a half hours.
42 hours