Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.
1 ft3 = 12*12*12 in3 = 1728 in3 So 0.524 ft3 = 1728*0.524 in3 = 905.472 in3
10 000 cm3
1 dm3 = 1000 cm3 :)
Volume per foot = (pi) R2 L = (pi) (15 in)2 (12 in) = 2700 pi in3 = 8,482.3 in3 = 36.72 gallons .
88 in3 * 2.543 cm3/in3 ≈ 88 in3 * 16.387 cm3/in3 ≈ 1442 cm3
2800 kg/m3 (2.8 g/cm3 )(0.098 lb/in3) --- alloys range anywhere from 0.097 lb/in3 (2.7 g/cm3) to 0.103 lb/in3 (2.9 g/cm3)
2800 kg/m3 (2.8 g/cm3 )(0.098 lb/in3) --- alloys range anywhere from 0.097 lb/in3 (2.7 g/cm3) to 0.103 lb/in3 (2.9 g/cm3)
First, we need to calculate what 1 cubic inch is in millilitres (mL). 1 mL is equal to 1 cubic centimetre (cm3), and the length of 1 inch is 2.54 cm. 1 in3 = 1 in × 1 in × 1 in = 2.54 cm × 2.54 cm × 2.54cm = 2.543 cm3 = 16.387064 cm3 Therefore, there are 16.39 millilitres per cubic inch (mL/in3). 5.9 L is 5900 mL, or 5900 cm3. So, now divide that by the number of mL/in3. 5900 mL / 16.387064 mL/in3 = 360.04009 in3 That means there are about 360 cubic inches in 5.9 L.
178.173 lbs of lead 433.526 in3 times (16.39 cm3 over 1 in3) times (11.4 g over 1 cm3) times (1 kg over 1000 g) times (2.2 lbs over 1 kg)= 178.173 lbs of lead.
There are exactly 231 in3 in a 50 gallon drum, which is also equal to roughly 3,785 cm3.
lb/ft3, kg/m3, 16.01846. lb/in3, kg/m3, 27679.90. lb/ft3, g/cm3, 0.01601846 ... in3/lb, cm3/kg, 36.127. W/(m K), BTU in /(hr ft2 F), 6.9334713 ...
Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.Assuming that 1 in3 is meant to be 1 m3, the answer is 100*100*100 = 1 million.
7.86 g/cm3 - 7860 kg/m3 -ALSO- 0.283 lb/in3
487.68 cm3 or 75.59 in3 is. (rounded)
The density of pure aluminum near room temperature is 2.70 g/cm3. 2.70 g/cm3 ÷ 28.34952 g/oz x 16.38706 cm3/in3 ≈ 1.56 oz/in3 ... so one half cubic inch weighs 0.78 oz.
1 ft3 = 12*12*12 in3 = 1728 in3 So 0.524 ft3 = 1728*0.524 in3 = 905.472 in3