125 ml = 1 liter 1 liter + 0.125 liter = 1.125 liters
1 liter = 100 centiliters 1 centiliter = 0.01 liter
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
milli is metric for 1/1000. therefore there are 1000 millileters in a Liter
0.7 L 1 liter = 100 centiliters 1 centiliter = 0.01 liter
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
The pH of 1 corresponds to a concentration of 0.1 M HCl. In 1 liter of solution, there would be 0.1 moles of HCl present.
To find the molarity of the resulting solution, we need to calculate the total moles of urea in both solutions and then find the total volume of the mixed solutions. Next, we divide the total moles of urea by the total volume in liters to get the molarity. After performing these calculations, the molarity of the resulting solution would be around 0.67M.
The concentration in moles of a substance in the solution
To make 1 liter of a solution with a concentration of 2 moles per liter, you would need to dissolve 2 moles of the solute in enough solvent to make up a final volume of 1 liter. This is done by adding the solute gradually to the solvent while stirring until it is completely dissolved.
3 moles in 1 liter = 3 M
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
0.1 molar HCl means that there is 0.1 moles of hydrochloric acid dissolved in 1 liter of solution. It indicates the concentration of the acid in the solution, with molarity representing the number of moles of solute per liter of solution.
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
To calculate the volume of solution needed, use the formula: Volume (in liters) = Moles / Molarity. For this case, the volume of solution needed to dissolve 0.25 moles of NaCl to make a 3.0M solution is 0.083 L or 83 mL. This volume corresponds to the amount of solution required to reach the desired concentration.
The concentration of ethanol in a solution is typically stated in terms of molarity, which is the number of moles of solute (ethanol) per liter of solution. The molarity can be determined by dividing the number of moles of ethanol by the volume of the solution in liters.
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!