27.
1 ÷ 3 = 0 r 3 → first multiple of 3 in the range 1-81 is 1 x 3 = 3
81 ÷ 3 = 27 → last multiple of 3 in the range 1-81 is 27 x 3 = 3
→ there are 27 - 1 + 1 = 27 multiples of 3 in the range 1-81, which are:
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81.
They are multiples of 1, 3, and 9.
Techcially all numbers are divisible by 81, however many would result in a decimal answer. If you mean how many numbers are divisible by 81 and have an integer answer, then it is "all multiples of 81" - e.g 81 x 2, 81 x 3 etc...81, 162, 243 and keep adding 81 forever.
81 84 87
Because 9 is a multiple of 3, the common multiples of 3 and 9 are the multiples of 9. The first 10 common multiples of 3 and 9 are 9, 18, 27, 36, 45, 54, 63, 72, 81, and 90.
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
1, 3 and 9 are common factors of 27, 45 and 81. 27, 45 and 81 are multiples of 1, 3 and 9.
They are multiples of 1, 3, and 9.
The multiples of 243 is 1, 3, 9, 27, 81, and 243.
The multiples of 81 are infinite. The factors of 81 are: 1, 3, 9, 27, 81.
They are multiples of 1, 3 and 9.
1, 3 and 9
Techcially all numbers are divisible by 81, however many would result in a decimal answer. If you mean how many numbers are divisible by 81 and have an integer answer, then it is "all multiples of 81" - e.g 81 x 2, 81 x 3 etc...81, 162, 243 and keep adding 81 forever.
Incorrect. Instead they are factors of I, 3 and 9.
3 x 3 x 3 x 3
1, 3, 29, 87.
The Multiples of 27: 27, 54, 81, 108, 135, .... Factors of 27: 1, 3, 9, 27 and 35. (27 = 33)
The factors of 81 are 1, 3, 9, 27, and 81.The factors of 162 are 1, 2, 3, 6, 9, 18, 27, 54, 81, and 162.81 is the first common multiple over 80 of 81 and 162.