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How many natural nos between 101 and 999 divisible by both 2 and 5?
Wiki User
∙ 10y ago
multiples of 10 will be divisible by 2 and 5
So Ap is 110,120,130....990
here 990 is the nth term
ie an=990
a+(n-1)d=990
110+(n-1)10=990
(n-1)10=990-110
(n-1)=880/10
n-1=88
n=88+1
n=89
Wiki User
∙ 10y ago
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