Well this depends. The number 9 only appears once (duh). There are 19 integers between 1 and 100; however, there is an infinite amount of nines on the number line....
The digit 9 appears in a total of 20 integers between 1 and 100.
9 19 29 39 49 59 69 79 89 90 91 92 93 94 95 96 97 98 99
Most people forget that 99 is actually two nines.
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
101
99 + 9(9 - 9)= 99 + 90 = 99 + 1 = 100
101
Not including 1 and 100, 99
There are exactly 20 Nines. 9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98 which totals 18 and the last number 99 has 2 nines and therefore 20 nines in total.
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
101
There are 11 nines in the numbers from 1 to 100: 9, 19, 29, 39, 49, 59, 69, 79, 89, and 99.
9x9=81 9 9=18 9 to the power 0=1 81 18 1=100
99 + 9(9 - 9)= 99 + 90 = 99 + 1 = 100
Well there will be 1 nine for all the 9s in the units column (9, 19, 29 etc.), and 1 nine for all the numbers with 9 in the tens column (90, 91, 92 etc.). So the answer is 20.
101
25 numbers are between 1-100.
100
The sixes between 1 and 100 are:6162636465660616263646566676869768696Therefore, there are 20 digit sixes between 1 and 100.
Not including 1 and 100, 99