Well this depends. The number 9 only appears once (duh). There are 19 integers between 1 and 100; however, there is an infinite amount of nines on the number line....
The digit 9 appears in a total of 20 integers between 1 and 100.
9 19 29 39 49 59 69 79 89 90 91 92 93 94 95 96 97 98 99
Most people forget that 99 is actually two nines.
10
11
20
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
101
99 + 9(9 - 9)= 99 + 90 = 99 + 1 = 100
101
Not including 1 and 100, 99
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
101
There are 11 nines in the numbers from 1 to 100: 9, 19, 29, 39, 49, 59, 69, 79, 89, and 99.
99 + 9(9 - 9)= 99 + 90 = 99 + 1 = 100
101
25 numbers are between 1-100.
100
Not including 1 and 100, 99
There are 90 two-digit whole numbers between 1 and 100.
The only consecutive primes between 1 and 100 are 2 and 3.
208 times,from 1 to 100 there r 11 nine such as 9 , 19 , 29, 39, 49,59, 69,79, 89, 99 its prove there are 11 nines so up to 800 there are 11*8=88 nines and from 900 to 1000 there are 100(901, 902,903......)+ 10 ( 990,991,992.....)+10(909,919,929,939....)=120 that means there are in total 88+120=208 nine in 1 to 1000
there are 98