Required numbers from 200 and 300 are 207,217,227,237,247,257,267,270,271,272,273,274,275,276,278,279,287,297 these are the numbers
therefore, the answer is 18
19 of them
18
There are 4*3 = 12 such numbers.
I assume you mean "six numbers" rather than "sox numbers". If the numbers are all distinct (i.e none of them are in the set of thirty numbers more than once), then there are 30!/(24!6!) ways of choosing six numbers, where "!" is the factorial of that number.
if we do not want to use the same number more than once then the answer is: 49*48*47*46*45*44 however if we can use a number more than once the solution is: 49^6
1. The numbers 1 through 99 are 99 different numbers; each one occurs once.
19 do.
19 of them
19.
To find the LCM (Lowest Common Multiple) of many numbers, find the prime factors of each number. Write down each prime factor once. If it occurs in more than one of the numbers, you should write it down once, but if it occurs more than once in a number, write it down that many times. Once you have found all the prime factors like this, you can multiply them all together to form the LCM.ExampleWhat is the LCM of 36, 16 and 27?36 = 2x2x3x316 = 2x2x2x227 = 3x3x3The prime factor 2 occurs the most in 16. Here it occurs 4 times.The prime factor 3 occurs most in 27. Here it occurs 3 times.Therefore, the LCM is 2x2x2x2x3x3x3 = 432
18: 209-219-229-239-249-259-269-279-289 and 290-291-292-293-294-295-296-297-298 (but not 299)
Twenty of them from 9 to 99
Once, 2 Is Only Listed Once Because No Other Number Is 2
The mode is the number that occurs most often, but as both numbers appear once, there is no mode.
5 x 10 = 50 Therefore, fifty only occurs once in a hundred.
None.
19 or 20 ( if you count 66 as double)