19 of them
There are 4*3 = 12 such numbers.
I assume you mean "six numbers" rather than "sox numbers". If the numbers are all distinct (i.e none of them are in the set of thirty numbers more than once), then there are 30!/(24!6!) ways of choosing six numbers, where "!" is the factorial of that number.
if we do not want to use the same number more than once then the answer is: 49*48*47*46*45*44 however if we can use a number more than once the solution is: 49^6
1. The numbers 1 through 99 are 99 different numbers; each one occurs once.
19 of them
The mode is the number that occurs most often, but as both numbers appear once, there is no mode.
To find the LCM (Lowest Common Multiple) of many numbers, find the prime factors of each number. Write down each prime factor once. If it occurs in more than one of the numbers, you should write it down once, but if it occurs more than once in a number, write it down that many times. Once you have found all the prime factors like this, you can multiply them all together to form the LCM.ExampleWhat is the LCM of 36, 16 and 27?36 = 2x2x3x316 = 2x2x2x227 = 3x3x3The prime factor 2 occurs the most in 16. Here it occurs 4 times.The prime factor 3 occurs most in 27. Here it occurs 3 times.Therefore, the LCM is 2x2x2x2x3x3x3 = 432
Twenty of them from 9 to 99
Once, 2 Is Only Listed Once Because No Other Number Is 2
Platypuses lay between one and three eggs at a time. This occurs once during each breeding season.
5 x 10 = 50 Therefore, fifty only occurs once in a hundred.
18: 209-219-229-239-249-259-269-279-289 and 290-291-292-293-294-295-296-297-298 (but not 299)