There are 21 dots on 1 dice so there are 42 in two dice
There are 3 odd numbers since there are a total of 6 consecutive numbers on a dice. For example, the numbers 1 2 3 4 5 6 are on a dice, so the odd numbers are 1, 3, and 5.
163759438475047695685695034395784593850835943859458474836937657 i have just tried it
2, 3, 5
11 outcomes if the dice are indistinguishable, 36 otherwise.
If you roll two dice and add the numbers together, you might get 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, so there are eleven possibilities total. One is not included in this list because that would mean the first dice would roll a one and the second dice would roll a...zero? That's impossible!
There are 21 combinations.
There are 3 odd numbers since there are a total of 6 consecutive numbers on a dice. For example, the numbers 1 2 3 4 5 6 are on a dice, so the odd numbers are 1, 3, and 5.
Three of them and they are 2, 4 and 6
there are (2, 3, 5) only 3 prime numbers on a single dice. 1 is not considered a prime number.
2 each of the numbers 1 thru 6. ---------------------------------- This can be answered in many ways: --- There are twelve faces on two dice, each with a number --- The are six different numbers on the dice faces --- There are 36 possible combinations of two dice --- --- They can total between 2 and 11 --- --- There are 21 different possible pairs (all but six of which can appear two ways)
Eight numbers.
The question is underspecified since the answer depends on the numbers on the dice. If all the numbers on both the dice are the same, there is clearly only one outcome. If the dice have 4 different numbers, then there can be 16 different outcomes. If the numbers on each die are 1,2,3 and 4 (or any four numbers in arithmetic sequence) there will be 7 outcomes.
6
3
Two.Two.Two.Two.
3
163759438475047695685695034395784593850835943859458474836937657 i have just tried it