There are 100 in the 400s.
In the 100s, 200s, and 300s, the ones place or the tens place could be 4. There are 10 numbers with a 4 in the ones place in each 100. There are 10 numbers with a 4 in the tens place in each 100. There is one overlap where there is a 4 in both the tens and the ones place. So, there are 19 numbers with a 4 as a digit in the each 100.
Therefore, there are (19 x 3) + 100 = 157 numbers with a 4 as one of the digits.
Here are the numbers in the 100s with a 4 in the ones place:
104
114
124
134
144
154
164
174
184
194
Here are the numbers in the 100s with a 4 in the tens place:
140
141
142
143
144
145
146
147
148
149
These lists have 20 numbers, but 144 is duplicated, so there are 19 numbers with 4 as a digit. The same will apply to the 200s and 300s. There will be a 4 in every number in the 400s, since the hundreds digit will always be a 4.
What the correct answer
I thing 6484. Am I correct ?
258 fours
157
176
There are 6484 digits BETWEEN the two given numbers.
There is only one number and that is 123456.
223
The number is: 36725918 In descending order that is: 98765321 The pairs of numbers that have as many digits between them in both are: 3,9 5,8 6,7 So there are three pairs.
176
I think its more then 20
19 do.
Only one. 123456.
Twenty of them from 9 to 99
There are 6484 digits BETWEEN the two given numbers.
There is only one number and that is 123456.
223
123
The number is: 36725918 In descending order that is: 98765321 The pairs of numbers that have as many digits between them in both are: 3,9 5,8 6,7 So there are three pairs.
The sum of the number of digits in all the numbers between 31 and 400 inclusive is 1041.
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundredβs place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.