If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
from 3 digits (10x10) to 4 digits (99X99)
-89
6*5*4*3*2*1=720 possible numbers
90. all the numbers from 10 through 99
90 of them.
there are 89 twodigits in whole numbers
Exactly 2: 243 of them.
1
5.8x10=58. There are exactly 2 digits in 58.
88 of them.
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
Zero; all six digit numbers have six digits. Dude.. i m asking 6 digit numbers, containing only 4 different digits..!! e.g.:123412.. with only 2 digits repeated..!! My guess is: 10*9*8*7*4*3 but I'm also guessing that is wrong- sorry!
5^4
2*3*3*3*3 = 162
Not 2 numbers - 2 digits. The digits 0 and 1.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.