95 = 5 * 19 both of which are prime, so 95 has 4 divisors as does any number that is the product of 2 primes.
The divisors are 1,5,19 and 95.
1, 5, 19 and 95.
5 goes into 95. 95 divided by 5 = 14
1 and five.
The number of times 2 goes into 95 can be calculated by dividing 95 by 2. The result is 47 with a remainder of 1. Therefore, 2 goes into 95 a total of 47 times with a remainder of 1.
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
They are: 1, 5, 19 and 95
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
95 goes in to 100 once.
5 times 19x5=95
6
16 of them.
These are all the whole numbers that go into 190 evenly: 1, 2, 5, 10, 19, 38, 95, 190.
5*19 = 95
95 times.
1 with remainder 45.
21 with remainder 5.
31 with remainder 2.