126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126.
1,2,3,6,7,9,14,18,21,42,63,126. (I didn't plagarize this)
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
To determine if 126 is divisible by 9, we need to check if the sum of its digits is divisible by 9. In this case, 1 + 2 + 6 = 9, which is divisible by 9. Therefore, 126 is divisible by 9.
126 is divisible by 2, 3 and 9 but not the other 2 126/2= 63 126/3= 42 126/9= 14
No, 120 or 126 are divisible by 6.
The numbers 21 and 126 are divisible by seven. The numbers 88 and 255 have a remainder when divided, so they are not divisible by seven.
All multiples of 126, which is an infinite number.
Two numbers: 126 and 147
1,2,3,6,7,9,14,18,21,42,63,126. (I didn't plagarize this)
3 is not divisible by 126. 126 is divisible by 3.
126
only 324 is divisible by 4
324
324
Any element of the set of numbers of the form 126*k, where k is an integer, is evenly divisible.
126 is divisible by 6 and 9
To determine if 126 is divisible by 9, we need to check if the sum of its digits is divisible by 9. In this case, 1 + 2 + 6 = 9, which is divisible by 9. Therefore, 126 is divisible by 9.