To determine the number of numbers that can be formed using the digits 1, 2, 3, 4, 5, and 6 without repetitions and less than 500, we first consider the hundreds place. Since the number has to be less than 500, the hundreds place can only be filled with 1, 2, or 3. For the tens and units place, any of the remaining digits can be used. Therefore, there are 3 choices for the hundreds place, 4 choices for the tens place, and 3 choices for the units place, giving a total of 3 x 4 x 3 = 36 numbers that can be formed.
There are 60480 numbers.
# 230 # 203 # 320 # 302
1 set
There are 4^6 = 4096 such numbers.
If the digits are all different then 18. Otherwise, 192.
pizza
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
2,401
10,000
Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
5^4
15 of them.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
99999
256