I don't think that there is an answer.
41 is the only odd number in this list
42
Twenty of them
9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.
There are several odd numbers between 42 and 64. One such is 61.
45, 63, 81, 99, 117
I don't think that there is an answer.
41 is the only odd number in this list
42
Start out looking at them. 7x1=7 odd 7x2=14 even 7x3=21 odd 7x4=28 even 7x5=35 odd 7x6=42 even... so it looks like half might be even and half odd, This is because if we look at the numbers 1-14, ie 1,2,3,4,5,6,7,8,9,10,11,12,13. and 14, they alternate odd and even and since 7 is odd and odd times an even is always an even number and an odd times an odd is always an odd number. So to answer the question we need only look at the number of odd numbers between 1 and 14 inclusive. There are 6 so 1,3,5,7,9,11,13 give odd multiples ANSWER: so 7 odd multiples of 7 between 1 and 100
Twenty of them
None that are all odd numbers. But, there are two sets of three consecutive numbers containing a mix of even/odd that add up to 120. They are 39, 40 and 41 and also 38, 40 and 42.
There are two: 42 and 84.
Three: 36, 42, 48.
9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.
Including 10 and 53 there are 44 numbers. Excluding 10 and 53 there would be 42 numbers.1011121314151617181920212223242526272829303132333435363738394041424344454647484950515253