We have to assume that digits can be repeated ... if they can't,
then no 5-digit numbers can be formed with only three digits.
The first digit can be either 3 or 5 . . . 2 choices.
The second digit can be any one of 3.
The third digit can be any one of 3.
The fourth digit can be any one of 3.
The fifth digit can be any one of 3.
Total possibilities = (2 x 3 x 3 x 3 x 3) = 162.
There are 5460 five digit numbers with a digit sum of 22.
There are 2000 possible five digit numbers that can be formed from the digits 02345 that are divisible by 2 or 5 or both. To be divisible by 2, the last digit must be even, namely 0, 2 or 4 (in the digits allowed). To be divisible by 5, the last digit must be 0 or 5. Thus to be divisible by 2 or 5 or both, the last digit must be 0, 2, 4 or 5 (a choice of 4). Presuming that a 5 digit number must be at least 10000, then: For the first digit there is a choice of 4 digits (2345); for each of these there is a choice of 5 digits (02345) for the second, making a total so far of 4 x 5 numbers; for each of these choices for the first and second digits there is a choice of 5 digits (02345) for the third digit making the total so far (4 x 5) x 5 numbers; for each of these choices for the first three digits there is a choice of 5 digits (02345) for the fourth digit making the total so far (4 x 5 x 5) x 5 numbers; for each of these choices for the first four digits there is a choice of 4 digits (0245 - as discussed above) for the last digit, giving a total of (4 x 5 x 5 x 5) x 4 numbers. So the total number of five digit numbers so formed is: number = 4 x 5 x 5 x 5 x 4 = 2000.
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
0,2,4,6,8
Including the leading zero, the smallest number you can make from the digits 03418 is 01348. Without the leading zero in the ten thousands column, the smallest number you can form from the digits 03418 is 10348.
It is 120 if the digits cannot be repeated.
the largest five digit number that can be formed using the digits 7 and 9 is 97,000
3
How about 256
94205 if digits are not to be repeated and 99999 if digits can be repeated
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
All five digit numbers have three digits. The smallest five digit whole number is 10,000
A five digit number is a number consisting of five digits. eg. 12345 54321 98765
50
There are 5460 five digit numbers with a digit sum of 22.
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
65390,93650,69530,